Integral calculation in Volume 1 of junior high school

Integral calculation in Volume 1 of junior high school

1、 1. A + (2b-3c-4d)=_________ ；
2、a-(-2b-3c+4d)=________ ；
3、(m-n)-3(z-p)=________ ；
4、3x-[5x-(2x-1)]=________ ；
5、4x2-[6x-(5x-8)-x2]=___________ ；
2、 Simplification (28 points)
1、(1)(3x+5y)+(5x-7y)-2(2x-4y)；
(2)5ab-{1、a+(2b-3c-4d)=
2、a-(-2b-3c+4d)=
3、(m-n)-3(z-p)=
4、3x-[5x-(2x-1)]=
5、4x2-[6x-(5x-8)-x2]=
6、(3x+5y)+(5x-7y)-2(2x-4y)；
7、5ab+[2a2b+(a2b-3ab)]-2a2b}
3、 Evaluation after simplification (16 points)
(2x2-x-1) - (x2-x -) + 3 (x2-1), where x = 1
4、 1, 7x-3y-4z = - (_________ )；
2、a2-2ab-a-b=a2-2ab-(_________ )；
3、5x3-4x2+2x-3=5x3-(_________ )-3；
4、a3-a2b+ab2=-(_______ )+ab2=a3-(________ )；
5、5a2-6a+9b=5a2-3(_____ )=-6a-(______ )；
6、x3-3x2y+3xy2-y3=x3-3x2y-(_____ )=x3-y3-(______ )；
5、 (1) (x3-4x2y + 5xy2-3y3) - (- 2xy2-4x3 + X2Y);
(2) Subtract 3a4-a3 + 2a-1 from a polynomial to get 5A4 + 3a2-7a + 2
6、 First simplify the following formula, then evaluate (45 points)
(1) X-2 (x -) + 3 (x +), where x = - 4;
(2) (3xy-2x2) - (2x2-y2) - (y2-2xy) + (- Y2 + 5x2 + XY), where x =, y = -;
(3) 5xyz - {2x2y - [3xyz - (4xy2-x2y)]} where x = - 2, y = - 1, z = 3;
There are many questions. Come on!