Let f (x) be a periodic function, and the minimum positive period is 2, and f (1 + x) = f (1-x), if - 1

Let f (x) be a periodic function, and the minimum positive period is 2, and f (1 + x) = f (1-x), if - 1

The minimum positive period is 2
x∈[1, 3]
x-2∈[-1, 0]
So f (x) = f (X-2) = - (X-2) = - x + 2
That's what we want