The relationship between the velocity and displacement of the uniform velocity linear motion. Formula: v2 I'm a freshman in high school, so try to answer in detail. It's better to have some symbols to explain
The formula V & # 178; - V0 & # 178; = 2aX is very practical, but it has no practical meaning
Because it's a reversal of other formulas
deduction:
From a = (vt-v0) / T and S = V (average) t, it is very simple to deduce the velocity formula of uniform acceleration linear motion with zero initial velocity
From a = (vt-v0) / T
vt=v0+at
Because V0 = 0
So VT = at
The displacement formula of uniform acceleration linear motion with zero initial velocity is derived
The average velocity V (average) = (V0 + VT) / 2 due to uniform velocity variation
V0 = 0, so V (average) = VT / 2 is substituted by S = V (average) t
s=(vt)t/2
And VT = at
So s = att / 2 = at ^ 2 / 2
If you don't understand the above formula, please let me know