When the engine speed is n = 3000r / min, what is the angular velocity ω? What is the period T? The answer is 100 π rad / s, 0.02s But the first question: 3000r / min. isn't ω 3000 laps × 360 degrees divided by 60 seconds? How can 18000 be obtained Please write down the correct process and explain where my solution is wrong~

Let's go. 3000 / 60 = 50R / s, this is F. then we use ω = 2 π F. so ω is 100 π. Then we use ω = 2 π / T to calculate t equal to 0.02

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