What's the volume ratio between the inscribed ball and the circumscribed ball of a cube? I think the radius of the circumscribed ball is two-thirds root

The radius of the outfall is certainly not 2 / 2
It's easier to consider diameter,
If the length of the diagonal of the face is 2, then the diagonal of the cube is the root (root 2 ^ 2 + 1 ^ 2) = root 3
The radius is the root of two three
Similarly, the radius of the inscribed sphere is 2 / 2 root sign 2
So the volume ratio is the third power of the radius ratio,
The ratio of circumscribed to inscribed is equal to 3 root sign 3 to 2 root sign 2

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