Given three vertices a, B, C of △ ABC and a point P in the plane, if the vector PA + Pb + PC = AB, then the positional relationship between point P and △ ABC is? The relationship between PA and PC is obtained

Vector PA + vector Pb + vector PC = vector AB vector PA + vector Pb + vector PC vector AB = 0 vector PA + vector Pb + vector PC + vector Ba = 0 vector PA + vector PC + (vector Pb + vector BA) = 0 vector PA + vector PC + vector PA = 0 vector PC = - 2 vector PA P on the third equinox of AC

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