Let vertex a (1,1) B (5,3) C (4,5) be the vertex of △ ABC, find the coordinates of the center of gravity of △ ABC (1), the area of △ ABC passing through point a, etc (2) A linear equation that bisects the area of △ ABC through point a

The center of gravity coordinate is the average of ABC coordinates
So it's (10 / 3,3)
If it passes a, it will pass the midpoint of BC (9 / 2,4)
So k = (4-1) / (9 / 2-1) = 6 / 7
So Y-1 = 6 / 7 (x-1)
6x-7y+1=0

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