Any function f (x) defined on R can be expressed as the sum of an odd function g (x) and an even function H (x), X belongs to R, then, A,g(x)=x,h(x)=lg(10^x+10^-x+2) B,g(x)=1/2lg(10^x+1+x),h(x)=1/2lg(10^x+1+x) c,g(x)=1/2x,h(x)=lg(10^x+1)-x/2 D,g(x)=-1/2x,h(x)=lg(10^x+1)+x/2 Why not D

Any function f (x) defined on R can be expressed as the sum of an odd function g (x) and an even function H (x), X belongs to R, then, A,g(x)=x,h(x)=lg(10^x+10^-x+2) B,g(x)=1/2lg(10^x+1+x),h(x)=1/2lg(10^x+1+x) c,g(x)=1/2x,h(x)=lg(10^x+1)-x/2 D,g(x)=-1/2x,h(x)=lg(10^x+1)+x/2 Why not D

C H (x) = LG (10 ^ x + 1) - X / 2, then
h(-x)=lg(10^(-x)+1)+x/2
=lg[(1+10^x)/10^x]+x/2
=lg(10^x+1)-lg10^x+x/2
=lg(10^x+1)-x+x/2
=lg(10^x+1)-x/2
=H (x) is an even function
D is not even!