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A straight line passes through the point m (- 2,2) and the area of the triangle surrounded by the two coordinate axes is 1. The equation of the straight line is obtained First floor: why x = 0 and y = 0? I get the following formula: s △ = 1 / 2 (2k + 2) * (- 2 / K - 2) = 1
Let Y-2 = K (x + 2),
When x = 0, y = 2K + 2
When y = 0, x = - 2 / K - 2
∴S△=1/2 （2k+2）* （-2/k -2）=1
The solution is k = - 1 / 2 or - 2
The analytical expression of the linear equation is y = - 1 / 2x + 1 or y = - 2x-2
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