In the formula s = VT + 1 / 2at & # 178;, when t = 1, s = 13; when t = 5, Ms = 225, find the value of s when t = 2

In the formula s = VT + 1 / 2at & # 178;, when t = 1, s = 13; when t = 5, Ms = 225, find the value of s when t = 2

When t = 1, s = 13; when t = 5, s = 225, then
{13=v+1/2a (1)
225=5v+25/2a (2)
(2)-(1)*5
160=10a
a=16
Substituting (1)
13=v+8
v=5
therefore
s=vt+1/2at²
=5t+8t²
When t = 2
s=5*2+8*4=42
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