What is the difference or internal relationship between acceleration and velocity? What is the direction of velocity in S-T or V-T image?

The rate of change of velocity is acceleration
When the acceleration is large, the speed changes quickly
The relationship formula is
Acceleration a = velocity v / time t
A positive speed means going forward
A negative speed means reversing
But the speed has nothing to do with the acceleration
Acceleration is the rate at which speed increases or decreases
Acceleration is the ratio of the change of velocity to the time taken for the change (△ V / △ T). It is a physical quantity describing the change of velocity of an object. It is usually expressed as a, and the unit is m / S ^ 2. Acceleration is a vector, and its direction is the direction of the change of velocity (quantity) of the object and the square of the combined external force
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1. Why is acceleration in meters per second Why does the formula for calculating acceleration use half of the difference between the final velocity and the initial velocity
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3. The relationship between the displacement of a particle and time is: S = 4T + 2 times the square of T, the units of S and T are meter and second respectively, The relationship between displacement and time is: S = 4 * t + 2 * t * t Therefore, the relationship between velocity and time is v = DS / dt = 4 + 4 * t So the initial velocity of the particle is: V0 = 4 + 4 * 0 = 4m / s The relationship between acceleration and time is a = DV / dt = 4 So the acceleration of particle is a = 4m / S2 The relationship between the velocity and time is v = DS / dt = 4 + 4 * t Can you tell me how to push it out? We haven't learned derivative yet Please tell me v=ds/dt=4+4*t My feeling is that v = DS / dt = 4 + 2 * t is right
4. The relationship between the displacement of a particle and time is s = 4T + 2T square. If the units of S and T are m and s respectively, what are the initial velocity and acceleration of the particle
5. The relationship between the displacement of a particle and time is: S = 4T + 2t2, the units of S and T are m and s respectively,
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7. The relationship between the displacement of a particle and time is x = 4T + 2t2 + 3. If the units of X and T are meter and second respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2 b.0 and 4m / s2 C. 4m / s and 2m / S2 d4m / s and 0
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14. S = v0t + 1 / 2at square s = v0t-1 / 2at square what's the physical formula? Why didn't my teacher teach it,
15. S = VT + 1 / 2at ^ 2 VT ^ 2-v0 ^ 2 = 2As how can these two formulas be derived Ask for guidance
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18. In the high school physics formula, there is a formula for acceleration: the square of S = at. How can this formula be deduced?
19. In the formula s = VT + 1 / 2at & # 178;, when t = 1, s = 13; when t = 5, Ms = 225, find the value of s when t = 2
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