The relationship between the displacement of a particle and time x = 4T + 2T ^ 2 x T unit is meter and second, then the initial velocity and acceleration of the particle are x=4t+2t^2

You write the acceleration formula first
x=v0t+1/2at^2
x=4t+2t^2
Take a look at the two formulas and compare them
v0=4 a=4
Because the coefficients correspond

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1. The relationship between the displacement of a particle and time is x = 4T + 2t2 + 3. If the units of X and T are meter and second respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2 b.0 and 4m / s2 C. 4m / s and 2m / S2 d4m / s and 0
2. What is the unit of acceleration in the international system of units
3. The acceleration is 2.5 meters per second, and the displacement is 10 meters in the last two seconds
4. When an object moves in a straight line with uniform acceleration, it moves 10 meters in the second two seconds, and the acceleration is 2 meters every second square second. What is the average speed in the eighth two seconds?
5. When an object moves in a straight line with uniform deceleration, the initial velocity is 12 meters per second, the acceleration is 2 meters per second, and the displacement of the object in a second is 6 meters. How far can it move after that Why can't we do this According to v = V0 + at, we get 0 = 12 + (- 2) t, t = 6S is to calculate how long he stops Then use x = v0t + 1 / 2at2 to find out x = 36-6 = 30. Why can't we do this? Find out the reason and correct method
6. When an object moves in a straight line with uniform acceleration from a certain moment, its initial velocity is known to be four meters per second, and its acceleration is two meters per second
7. Why is acceleration in meters per second Or what does the second power of s represent? How did it come from
8. 1. It is proved that the difference of displacement is equal to a constant in a continuous and equal period of time in a uniform linear motion 2. It is proved that the instantaneous velocity in the middle of a period of time is equal to the average velocity in this period of time 3. The displacement of a particle moving in a uniform straight line is 24m and 64M respectively in two continuous equal time intervals, and each time interval is 4S. Calculate the initial velocity and acceleration of the particle. (solve by more than two methods)
9. It is proved that the difference of displacements in continuous equal time is equal to a constant
10. What does it mean that the displacement difference of uniform velocity linear motion in continuous equal time interval is a constant
11. The relationship between the displacement of a particle and time is: S = 4T + 2t2, the units of S and T are m and s respectively,
12. The relationship between the displacement of a particle and time is s = 4T + 2T square. If the units of S and T are m and s respectively, what are the initial velocity and acceleration of the particle
13. The relationship between the displacement of a particle and time is: S = 4T + 2 times the square of T, the units of S and T are meter and second respectively, The relationship between displacement and time is: S = 4 * t + 2 * t * t Therefore, the relationship between velocity and time is v = DS / dt = 4 + 4 * t So the initial velocity of the particle is: V0 = 4 + 4 * 0 = 4m / s The relationship between acceleration and time is a = DV / dt = 4 So the acceleration of particle is a = 4m / S2 The relationship between the velocity and time is v = DS / dt = 4 + 4 * t Can you tell me how to push it out? We haven't learned derivative yet Please tell me v=ds/dt=4+4*t My feeling is that v = DS / dt = 4 + 2 * t is right
14. What does the second power of s represent?
15. Why is acceleration in meters per second Why does the formula for calculating acceleration use half of the difference between the final velocity and the initial velocity
16. What is the difference or internal relationship between acceleration and velocity? What is the direction of velocity in S-T or V-T image?
17. How does the physical formula s = 1 / 2at come from?
18. S = v0t + 1 / 2at square The physical meaning of the expression and the meaning of each item
19. Why is the displacement formula s = v0t + 1 / 2at ^ 2
20. S = v0t + 1 / 2at square s = v0t-1 / 2at square what's the physical formula? Why didn't my teacher teach it,