Why is acceleration in meters per second Or what does the second power of s represent? How did it come from

Acceleration acceleration is a physical quantity and a vector in physics. It is mainly used in classical physics. It is generally expressed by the letter A. in the international system of units, the unit is m / S ^ 2

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1. 1. It is proved that the difference of displacement is equal to a constant in a continuous and equal period of time in a uniform linear motion 2. It is proved that the instantaneous velocity in the middle of a period of time is equal to the average velocity in this period of time 3. The displacement of a particle moving in a uniform straight line is 24m and 64M respectively in two continuous equal time intervals, and each time interval is 4S. Calculate the initial velocity and acceleration of the particle. (solve by more than two methods)
2. It is proved that the difference of displacements in continuous equal time is equal to a constant
3. What does it mean that the displacement difference of uniform velocity linear motion in continuous equal time interval is a constant
4. Why is the displacement difference of uniform velocity linear motion in continuous equal time interval a constant
5. Determine the acceleration of uniform linear motion 2, the displacement difference of continuous equal time is equal to at & sup2; how to deduce it? Please explain in detail The frequency of power supply used in the experiment of uniform variable speed linear motion is 50 Hz. Take a piece of paper as the starting point, and study how to calculate X1 from 0 to 40-1 X1 1-2 x2 = 62-3 X3 = 9
6. Is the average acceleration equal to the instantaneous acceleration in the uniform linear motion? Why? How to calculate the instantaneous acceleration? How to calculate the average acceleration?
7. It is proved that: (1) if the difference of displacement of an object moving uniformly in a straight line is a fixed value in any two continuous equal time, and the acceleration is a, the continuous equal time is t, and the difference of displacement is △ x, then △ x = at2. (2) in the uniformly variable linear motion, the instantaneous velocity at the midpoint of displacement is VX2 = V20 + v2t2
8. Please prove that the displacement difference of an object moving in a straight line with uniform speed change is a constant value in any two consecutive equal time periods. Let the acceleration be a and the time periods be continuous and equal If t is t and the displacement difference is Δ x, then Δ x = the square of a * t
9. After hitting the wall, the ball rebounds at the original speed. The contact time between the ball and the wall is 0.2 seconds
10. Physics problems in grade one of senior high school If a gymnast falls from a certain height, his center of gravity will drop about 15cm when his feet fall to the ground. What is the maximum limit height of a gymnast's jump? It's better to have a detailed explanation
11. When an object moves in a straight line with uniform acceleration from a certain moment, its initial velocity is known to be four meters per second, and its acceleration is two meters per second
12. When an object moves in a straight line with uniform deceleration, the initial velocity is 12 meters per second, the acceleration is 2 meters per second, and the displacement of the object in a second is 6 meters. How far can it move after that Why can't we do this According to v = V0 + at, we get 0 = 12 + (- 2) t, t = 6S is to calculate how long he stops Then use x = v0t + 1 / 2at2 to find out x = 36-6 = 30. Why can't we do this? Find out the reason and correct method
13. When an object moves in a straight line with uniform acceleration, it moves 10 meters in the second two seconds, and the acceleration is 2 meters every second square second. What is the average speed in the eighth two seconds?
14. The acceleration is 2.5 meters per second, and the displacement is 10 meters in the last two seconds
15. What is the unit of acceleration in the international system of units
16. The relationship between the displacement of a particle and time is x = 4T + 2t2 + 3. If the units of X and T are meter and second respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2 b.0 and 4m / s2 C. 4m / s and 2m / S2 d4m / s and 0
17. The relationship between the displacement of a particle and time x = 4T + 2T ^ 2 x T unit is meter and second, then the initial velocity and acceleration of the particle are x=4t+2t^2
18. The relationship between the displacement of a particle and time is: S = 4T + 2t2, the units of S and T are m and s respectively,
19. The relationship between the displacement of a particle and time is s = 4T + 2T square. If the units of S and T are m and s respectively, what are the initial velocity and acceleration of the particle
20. The relationship between the displacement of a particle and time is: S = 4T + 2 times the square of T, the units of S and T are meter and second respectively, The relationship between displacement and time is: S = 4 * t + 2 * t * t Therefore, the relationship between velocity and time is v = DS / dt = 4 + 4 * t So the initial velocity of the particle is: V0 = 4 + 4 * 0 = 4m / s The relationship between acceleration and time is a = DV / dt = 4 So the acceleration of particle is a = 4m / S2 The relationship between the velocity and time is v = DS / dt = 4 + 4 * t Can you tell me how to push it out? We haven't learned derivative yet Please tell me v=ds/dt=4+4*t My feeling is that v = DS / dt = 4 + 2 * t is right