When an object moves in a straight line with uniform acceleration from a certain moment, its initial velocity is known to be four meters per second, and its acceleration is two meters per second
v0=4m/s^2,a=2m/s^2
At the end of 2S, v = V0 + at = 4 + 2 * 2 = 8m / S
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- 1. Why is acceleration in meters per second Or what does the second power of s represent? How did it come from
- 2. 1. It is proved that the difference of displacement is equal to a constant in a continuous and equal period of time in a uniform linear motion 2. It is proved that the instantaneous velocity in the middle of a period of time is equal to the average velocity in this period of time 3. The displacement of a particle moving in a uniform straight line is 24m and 64M respectively in two continuous equal time intervals, and each time interval is 4S. Calculate the initial velocity and acceleration of the particle. (solve by more than two methods)
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- 7. Is the average acceleration equal to the instantaneous acceleration in the uniform linear motion? Why? How to calculate the instantaneous acceleration? How to calculate the average acceleration?
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- 12. When an object moves in a straight line with uniform acceleration, it moves 10 meters in the second two seconds, and the acceleration is 2 meters every second square second. What is the average speed in the eighth two seconds?
- 13. The acceleration is 2.5 meters per second, and the displacement is 10 meters in the last two seconds
- 14. What is the unit of acceleration in the international system of units
- 15. The relationship between the displacement of a particle and time is x = 4T + 2t2 + 3. If the units of X and T are meter and second respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2 b.0 and 4m / s2 C. 4m / s and 2m / S2 d4m / s and 0
- 16. The relationship between the displacement of a particle and time x = 4T + 2T ^ 2 x T unit is meter and second, then the initial velocity and acceleration of the particle are x=4t+2t^2
- 17. The relationship between the displacement of a particle and time is: S = 4T + 2t2, the units of S and T are m and s respectively,
- 18. The relationship between the displacement of a particle and time is s = 4T + 2T square. If the units of S and T are m and s respectively, what are the initial velocity and acceleration of the particle
- 19. The relationship between the displacement of a particle and time is: S = 4T + 2 times the square of T, the units of S and T are meter and second respectively, The relationship between displacement and time is: S = 4 * t + 2 * t * t Therefore, the relationship between velocity and time is v = DS / dt = 4 + 4 * t So the initial velocity of the particle is: V0 = 4 + 4 * 0 = 4m / s The relationship between acceleration and time is a = DV / dt = 4 So the acceleration of particle is a = 4m / S2 The relationship between the velocity and time is v = DS / dt = 4 + 4 * t Can you tell me how to push it out? We haven't learned derivative yet Please tell me v=ds/dt=4+4*t My feeling is that v = DS / dt = 4 + 2 * t is right
- 20. What does the second power of s represent?