The relationship between the displacement of a particle and time is x = 4T + 2t2 + 3. If the units of X and T are meter and second respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2 b.0 and 4m / s2 C. 4m / s and 2m / S2 d4m / s and 0

Let x = 4T + 2T ^ 2 + 3
And x = XO + VO * t + (1 / 2) at ^ 2
Quite
Vo=4m/s
a=4m/s^2
Another solution is as follows
V=dx/dt=d(4t+2t^2+3)/dt=4+4t
When t = 0, v = VO = 4m / s
a=dV/dt=d(4+4t)=4m/s^2
Choose a

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