The relationship between the displacement of a particle and time is s = 4T + 2T square. If the units of S and T are m and s respectively, what are the initial velocity and acceleration of the particle

Because the initial velocity VO and acceleration a are constant, so according to the formula s = VO * t + (1 / 2) * at ^ 2 and S = 4T + 2T ^ 2, we can get VO = 4 m / s, a = 4 m / S ^ 2 is the coefficient before t is VO, and the coefficient before T ^ 2 is a / 2. If we learn differentiation later, we can directly derive s, that is, v = DS / dt = 4 + 4T, a = DV / dt

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