If x / A + Y / b = 1, the distance from the abscissa A / 3 point to the left focus is greater than the distance from the abscissa A / 3 point to the right guide line, then the eccentricity range of the ellipse is larger
Suppose that this point is p, f is the left focal point, and pH is the distance from P to the right directrix,
Then: pf = a + e * A / 3, pH = A & sup2 / C-A / 3 = A / e-A / 3;
Because: pf > pH, so: a + e * A / 3 > A / e-A / 3, E & sup2; + 12e-3 > 0,
The solution is: e > - 6 + √ 39, so: - 6 + √ 39
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