Application of solving linear equation of one variable 1. Xiao Ming and Xiao Dong each have a number of extra-curricular books. The number of extra-curricular books of Xiao Ming is twice that of Xiao Dong. After Xiao Ming gave Xiao Dong 10 books, the number of extra-curricular books of Xiao Dong is three times that of Xiao Ming's remaining. How many extra-curricular books did Xiao Ming and Xiao Dong have? 2. The purchase price of a product is 2000 yuan, and the price is 3000 yuan. The store requires a discount of 5% of the profit. How much discount should the salesman give?

Application of solving linear equation of one variable 1. Xiao Ming and Xiao Dong each have a number of extra-curricular books. The number of extra-curricular books of Xiao Ming is twice that of Xiao Dong. After Xiao Ming gave Xiao Dong 10 books, the number of extra-curricular books of Xiao Dong is three times that of Xiao Ming's remaining. How many extra-curricular books did Xiao Ming and Xiao Dong have? 2. The purchase price of a product is 2000 yuan, and the price is 3000 yuan. The store requires a discount of 5% of the profit. How much discount should the salesman give?

One yuan a time!
1. If Xiaodong had x copies, Xiaoming would have 2x copies
Xiaoming has 2x-10 copies and Xiaodong has x + 10 copies
So we have the equation x + 10 = 3 * (2x-10)
It can be solved that x = 8, that is, Xiaodong originally had 8 books
Xiaoming has 2 * 8 = 16 books
2. To make a profit of 5% is to make a profit of 2000 * 5% = 100 yuan
In this way, the selling price of 2100 yuan can meet the requirements
Then the discount is 2100 / 3000 = 0.7, that is, 7% off to sell the product!