Find ∫ ln (e ^ x + 1) / e ^ x DX

A:
Let e ^ x = t
The original formula = ∫ ln (T + 1) / T ^ 2DT
=-ln(t+1)/t-ln|(t+1)/t|+C
=-ln(e^x+1)/e^x-ln[(e^x+1)/e^x]+C

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