Given the function f (x) = 2sinxcos (x + Pie / 6) - cos2x + m when x (x) The minimum value of M is - 3

Given the function f (x) = 2sinxcos (x + Pie / 6) - cos2x + m when x (x) The minimum value of M is - 3

F (x) = 2sinxcos (x + π / 6) - cos2x + M = sin (2x + π / 6) - sin (π / 2-2x) + m - sin (π / 6) = 2 * sin (2x - π / 6) * cos (π / 3) + m - Sin (π / 6) = sin (2x - π / 6) + m - 1 / 2F (x) minimum: m - 3 / 2; m = - 1.5