Logarithm of 7 / 48 with 2 as the radical + logarithm of 12 with 2 as the base minus logarithm of 42 with 2 as the base =(lg√7/48 +lg12 -1/2lg42)/lg2 =(lg√3+lg√7-1/2lg2-1/2lg3-1/2lg7)/lg2 =-0.5 How did step one get to step two?

Logarithm of 7 / 48 with 2 as the radical + logarithm of 12 with 2 as the base minus logarithm of 42 with 2 as the base
=(lg√7/48)/lg2 +lg12/lg2 -1/2(lg42/lg2)
=(lg√7/48 +lg12 -1/2lg42)/lg2
Note: the logarithm of B with a as the base = LGB / LGA

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