Let a = log log log with 1 / 3 as base 2, B = log log with 2 as base 3, C = (1 / 2) ^ 0.3 Then the relationship of a, B and C is
a=log1/3(2),b=log2(3),c=(1/2)^0.3
a=log1/3(2)1,c=(1/2)^0.3c>a
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