It is known that LG2 = A and Lg3 = B. try to use a and B to express the logarithm with 5 as the lower 12

lg2＝a,lg3＝b,
∴log12
＝lg(2²×3)/lg(10/2)
＝(2lg2+lg3)/(1-lg2)
＝(2a+b)/(1-a).

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