How can the logarithm with root 3 minus root 2 as the base 5 be transformed into the logarithm with root 3 plus root 2 as the base 1 / 5?

How can the logarithm with root 3 minus root 2 as the base 5 be transformed into the logarithm with root 3 plus root 2 as the base 1 / 5?

First notice: root 3 minus root 2 = reciprocal of root 3 plus root 2
Then, we can make the logarithm of root 3 minus root 2 as base 5 = X,
Then the x power of (root 3 minus root 2) is 5
That is, the x power of (1 / radical 3 + radical 2) is 5
That is: (1 / 5) x power = root 3 plus root 2
That is: x = the logarithm of 1 / 5 with root 3 and root 2 as the base
The proof is complete