The intersection of the functions y = x ^ 2 and y = 2x + 3 is a, B. A is on the right side of B. find the area of (1) a, B coordinates (2) triangle abo

x^2=2x+3
(x-3)(x+1)=0
x=3,y=9
x=-1,y=1
So a (3,9), B (- 1,1)
2) A is the perpendicular of x-axis, and x-axis is at a '(3,0)
B is the perpendicular of X axis, and X axis is at B '(- 1,0)
Triangle ABO area = trapezoid aa'b'b-triangle OAA '- Triangle OBB' = 1 / 2 [10 * 4-3 * 9-1 * 1] = 6

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