Find the area of the triangle formed by the intersection of the parabola y = - X & # 178; - x + 6 and the coordinate axis

RELATED INFORMATIONS

• 1. The intersection of the first-order function y = - 2x + B and the x.y axis forms a triangle. The area of the triangle is 9. How to find the first-order function?
• 2. The intersection of the functions y = x ^ 2 and y = 2x + 3 is a, B. A is on the right side of B. find the area of (1) a, B coordinates (2) triangle abo
• 3. The coordinate of the intersection of the function y = 2x-1 and the X axis is____ The coordinate of the intersection point with the Y axis is___ And the area of the triangle enclosed by the two axes is____
• 4. The function y = x + M & sup2; intersects the image of y = 4x-1 at the same point on the x-axis, and the value of M is______
• 5. It is known that the function y = [M + 2] x to the power of M + 4 - 4x + 1 [x ≠ 0] is a linear function Multiplication of powers of the same base
• 6. If the function y = (m-2) x3-m2 + m is a linear function, then the value of M is___ ．
• 7. When m, y = (M-4) x to the power of 2m + 1 + 4x-5 is a linear function
• 8. Given the function f (x) = x 2 + ax + 3, when x ∈ [- 2,2], f (x) ≥ A is constant, and the minimum value of a is obtained
• 9. Given the function f (x) = (x ^ 2 + ax + 11) / (x + 1) (a ∈ R), if f (x) ≥ 3 holds for any x ∈ n *, then the minimum value of a is equal to (17 / 3)
• 10. Given the function f (x) = cosx + ax ^ 2, when x is greater than or equal to 0, the minimum value of a with F (x) greater than or equal to 1 is k, and the value of K is obtained
• 11. Function y = ax & # 178; + BX + C (a ≠ 0) image vertex is (1,4) and C = 0, the triangle area formed by the intersection of the vertex of quadratic function and coordinate axis is__
• 12. If the quadratic function y = f (x) satisfies f (3 + x) = f (3-x), and f (x) = 0 has two real roots X1 and X2, then X1 + x2 = () A. 0b. 3C. 6D. Not sure
• 13. The quadratic function y = f (x) satisfies f (3 + x) = (3-x), and f (x) = 0 has two real roots x1, x2?
• 14. Given quadratic function, f (x) = ax & # 178; + BX + C (a ≠ 0), this paper proves that the equation f (x) = 1 / 2 [f (0) + F (1)] has two unequal real roots, and one root is in the interval (0,1)
• 15. Given the function f (x) = - A & # 178; X & # 179 / / 3 + ax & # 178 / / 2 + CX (a is not equal to 0), when a ≥ 1 / 2, if the real number equation f '(x) = 0 When a ≥ 1 / 2, if the real number equation f '(x) = 0 has two real number roots m, N, and | m | ≤ 1, | n | ≤ 1. Prove: - 1 / 4 ≤ C ≤ A & # - A
• 16. It is known that the vertex coordinates of the quadratic function y = f (x) are (- 32,49), and the difference between the two real roots of the equation f (x) = 0 is equal to 7
• 17. When the vertex of the image of quadratic function f (x) is known, m (- 2 / 3,49), the difference between the two equations f (x) = 0 is equal to 7, and the analytic expression of quadratic function f (x) is obtained
• 18. It is known that the vertex coordinates of the quadratic function y = f (x) are (3 / 2,49), and the difference between the two real roots of the equation f (x) = 0 is equal to 7,
• 19. It is known that the quadratic function FX = AX2 + BX (a, B are constants, and a is not equal to 0) satisfies the following conditions: F (- x + 5) = f (x-3), and the equation f (x) = x has real roots (1) Find the analytic expression of F (x); (2) whether there are real numbers m, n (m < n), so that the definition field and value field of F (x) are [M, n] and [3M, 3N]? Request the value of M, n
• 20. Given the function f (x) = x + 1 + X-2, draw the image of the function I'm in a hurry!