The range of independent variable X of function y = root 4x-1 / 2 is

The range of independent variable X of function y = root 4x-1 / 2 is

If y = root (4x-1 / 2)
Then the number in the root sign should be greater than or equal to 0
So it's one of (4x-2) > = 0
If the denominator of the fraction is 0, the fraction will be meaningful
So 4x-2 is not zero
The solution is: X is not equal to 1 / 8
But if x ＞ 1 / 8
The number in the root sign is less than 0
The radical does not hold
So to sum up: x < 1 / 8
If y = root [4x - (2:1)]
So the range is 4x - (1 / 2) > = 0
That is, X ＞ = 1 / 8
If y = (4x under the root) - 1 / 2
So the range is 4x ＞ = 0
That is, X ＞ = 0