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Given that the point P is a moving point on the right part of the image of quadratic function y = - x ^ 2 + 3x, the line y = - 2x + B (b > 0) intersects the X axis and Y axis at two points CD respectively, If △ PCD with CD as right angle side is similar to OCD of triangle, the coordinates of P can be obtained
P (x, - x ^ 2 + 3x) x > 0y = - 2x + B C: (B / 2,0); D (0, b) OC = B / 2, OD = B △ PCD of right angle side is similar to triangle OCD, CD ^ 2 = B ^ 2 / 4 + B ^ 2 = 5B ^ 2 / 4, CD = B radical 5 / 2 angle, CDO = angle, cdpcp = Tan angle, CDP * CD = Tan angle, CDO * CD = OC / OD * CD = B / 2 / b * radical 5 / 2 = B radical 5 / 4, let y = - x ^ 2 + 3x and X axis
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