Let a straight line passing through the left focus F1 of the ellipse x ^ 2 / 4 + y ^ 2 / 3 = 1 and with an inclination angle of 45 degrees intersect the ellipse and find the perimeter of the triangle abf2 at two points ab

From the parameters of the elliptic equation, we get: C = 1. Focus F1 (- 1,0), F2 (1,0). In addition, the slope of the line L passing through the focus F1 (- 1,0) is k = tan45 ° = 1. The equation of the line L is y = x + 1. (1). We substitute (1) into the elliptic equation: x ^ 2 / 4 + (x + 1) ^ 2 / 3 = 1

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