Tan1°tan2°+tan2°tan3°+ tan3°tan4°…… +tan59°tan60°=

tan（α-β）=（tanα-tanβ）/（1+tanαtanβ）tanαtanβ=【（tanα-tanβ）/ tan（α-β）】-1tan1°tan2°+tan2°tan3°+ tan3°tan4°…… +tan59°tan60°=【(tan1°- tan2°+ tan2°- tan3°…… + tan59°- ta...

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1. Tan30, tan60, I will ask for tan2, tan3, and so on
2. tan10°+tan50°=tan60°-tan60°tan10°tan50° Why does this equation hold?
3. Under the simplified radical sign (tan30 ° - tan50 °) + |tan50 ° - tan60 °|
4. （3+tan30*tan40+tan40*tan50+tan50*tan60)*tan10=?
5. Simplify Tan 30 ° + Tan 40 ° + Tan 50 ° + Tan 60 °
6. The value of tan10 ° + tan50 ° + 3tan10 ° tan50 ° is () A. -3B. 3C. 3D. 33
7. The results of Tan 60 ° + 2 sin 45 ° - 2 cos 30 ° are as follows______ ．
8. What is the result of Tan 60 ° + 2tan 45 ° - 2cos 30?
9. Calculation: tan60 ° + 2sin45 ° minus 2cos30 °=
10. Calculation: Tan 60 ° + sin 245 ° - 2 cos 30 °
11. sin40(tan10-3^1/2)=?
12. Tan 60? - (COT 45? + 2Sin 60?) (4cos 60?)
13. What is the value of tan44 ° * cot45 ° * tan46?
14. Find the value of tan44 ` cot45 ` tan46 ' Find the value of tan44 ` cot45 ` tan46 ' Note: tan44'means tan60 degree, and "'" means "degree". In addition, this is an exercise in the geometry book of grade three Note: tan44 'means tan44 degree, and "'" means "degree". In addition, this is an exercise in the geometry book of grade three (I'm sorry that the above caption is wrong) I don't understand what's written on the first floor
15. Find the value of tan44 ° cot45 ° tan46 °
16. What is the same angle trigonometric function
17. Trigonometric function problem! 2010 Zhejiang Li Shu In △ ABC, the edges opposite angles a, B and C are a, B and C, respectively. Given cos2c = - 1 / 4, find the value of sinc Only one of the answers is positive, but how to discard the negative?
18. In the acute angle △ ABC, the opposite sides of the inner angles a, B and C are a, B and C respectively. It is known that C = 2, 2sin2c-2cos2c = 1. Find (1) the radius of the circumscribed circle of △ ABC; (2) when B = 5 π 12, find the size of A
19. Trigonometric function problem cosacos2a - 1 = cos3a cos2acos(n-1) - cos(n-2)a = cosna Please tell me what formula to use
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