We know the maximum value of the function y = 4x / (x ^ 2 + 1) (x > 0). When we get the maximum value, what is x equal to

We know the maximum value of the function y = 4x / (x ^ 2 + 1) (x > 0). When we get the maximum value, what is x equal to

Y = 4x / (X & # 178; + 1) = 4 / [x + 1 / x], because x + 1 / X ≥ 2, then y ≤ 2, that is, the maximum value of Y is 2, then x = 1