Find the definition and range of the following function y = (3-2 ^ x) / (2 ^ x-1)

If the domain is 2 ^ X-1 ≠ 0, then x ≠ 0
Let t = 2 ^ x > 0, y = (3-T) / (t-1) = (1-T + 2) / (t-1) = - 1 + 2 / (t-1)
Because t > 0, 2 / (t-1) > 0, or 2 / (t-1) - 1, or y

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