Y = 3x-2 / x + 1 (x > 0)

Y = 3x-2 / x + 1 (x > 0)

y=(3x-2)/(x+1)
=[3(x+1)-5]/(x+1)
=3-5/(x+1)
Because x is greater than 0
So x + 1 > 1
So 0 < 1 / (x + 1) < 1
0<5/(x+1)<5
-5<-5/(x+1)<0
3-5<3-5/(x+1)<3
That is - 2 < 3-5 / (x + 1) < 3
So the range of Y is y ∈ (- 2,3)
Answer: y ∈ (- 2,3)