Find the range 1, y = (x + 2) / (x * x + 3x + 6) 2, y = 3x / (x * x + 4)
y=(x+2)/(x^2+3x+6)
yx^2+3yx+6y=x+2
yx^2+(3y-1)x+(6y-2)=0
This equation about X has a solution
Then the discriminant is greater than or equal to 0
So (3y-1) ^ 2-4y (6y-2) > = 0
9y^2-6y+1-24y^2+8y>=0
15y^2-2y-1
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