If the inequality a ≥ X & # 178; - 6x is [0,1] constant for any x, then the value range of the number a is | Math enthusiast | Mathematical art

If the inequality a ≥ X & # 178; - 6x is [0,1] constant for any x, then the value range of the number a is

x^2-6x=x(x-6)
When x belongs to [0,1], the range of x ^ 2-6x is [- 5,0], so the value range of a is a > = 0

RELATED INFORMATIONS

1. Given the function f (x) = 4x ^ 2-4ax, X ∈ [0,1], the solution set of inequality | f (x) | > 1 about X is an empty set, then the value range of real number a satisfying the condition =?
2. Given that the function f (x) = x ^ 2 + 4x + 3, the inequality f (x) > A is r for any x, then the value range of real number a is?
3. Let t be a real number, f (x) = x + T / x2 + 1, if x belongs to [- 1,2], then the inequality f (x)
4. Given the function f (x) = (x2-x-1 / a) e ^ ax (a > 0), if the inequality f (x) + 3 / a > = 0 holds for X ∈ (- 3 / A, + infinity), then the value range of real number a is?
5. Given the function FX = | X-1 | + | x-3 | (1), find the value range of X, make FX a constant function (2) if the inequality f about X The known function FX = | X-1 | + | x-3| (1) Find the value range of X so that FX is a constant function (2) If the inequality f (x) - a ≤ 0 about X has a solution, find the value range of real number a
6. Given the function FX = {X & # 178; + 1, X ≥ 0 and 1, x < 0, then the value range of X satisfies the inequality f (1-x & # 178;) > F (2x)
7. Find the range of y = 3x + 1 / 2x-1, X ∈ [1,2]
8. Y = (1 / 3) ^ (2 / 3x-1), find the range of function y=(1/3)^[2/(3x-1)]
9. If f (x) is an odd function defined on R, and X ∈ (0, + ∞), f (x) = LG (x + 1), find the expression of F (x) and draw the diagram
10. Given that function f (x) is an odd function on R, and x > 0, f (x) = 1, try to find the expression of function y = f (x)
11. (1) If the inequality | x + 1 | + | X-1 | K holds, the value range of K is obtained School starts the day after tomorrow·········· Better have a little process
12. If the range of function y = 4 - √ (3-2x-x ^ 2) is - 1 < a < 0, then the inequality ax ^ 2 - (a ^ 2 + 1) x + A
13. Find the range: (1) y = INX (0)
14. Find the range y = Log & # 8322; (1 + X & # 178;)
15. The range of function y = √ (4-x) + log (0.5) x is Such as the title I figured it out to be - 2 to root 3 ', but it's wrong at my level
16. Find the range of function y = - [log (x ^ 2 + 2)] ^ 2-log (x ^ 2 + 2) + 5 with 1 / 4 base
17. The range and monotone interval of function y = log (x-x ^ 2) (a > 0, a ≠ 1) y=loga(x-x^2)(a>0,a≠1) A is the base On the first floor, your answer seems to be wrong
18. The range of function y = log 1 / 2 x, X ∈ (0.8) is
19. Find the range of function y = log2 (x) + log x (2x)
20. Find the range of function y = (log2 X / 4) × (log √ 2 2x), (x ≥ 2)