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Find the range of function y = (log2 X / 4) × (log √ 2 2x), (x ≥ 2)
Log2 X / 4 = log2 x-log2 4 = log2 x-2log √ 2 2x = log √ 2 2 + log √ 2 x = LG2 / LG √ 2 + lgx / LG √ 2 = LG2 / (1 / 2) LG2 + lgx / (1 / 2) LG2 = 2 + 2lgx / LG2 = 2 + 2log2 x, so y = (log2 X-2) (2 + 2log2 x) let a = log2 x, x > = 2, so a > = log2 2 2, 2 = 1y = (A-2) (2a + 2) = 2A ^
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