The range of function f (x) = 2x − X2 (0 ≤ x ≤ 3) x2 + 6x (− 2 ≤ x ≤ 0) is______ .
∵ function y = 2x-x2, 0 ≤ x ≤ 1 range B = [- 3, 1] function y = x2 + 6x, - 2 ≤ x ≤ 0 range C = [- 8, 0], so function f (x) = f (x) = 2x − X2 (0 ≤ x ≤ 3) x2 + 6x (− 2 ≤ x ≤ 0) range B ∪ C = [- 8, 1], so the answer is [- 8, 1]
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