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∵函數y=2x-x2,0≤x≤1的值域B=[-3,1]函數y=x2+6x,-2≤x≤0的值域C=[-8,0]故函數f(x)=f(x)=2x−x2(0≤x≤3)x2+6x(−2≤x≤0)的值域是B∪C=[-8,1]故答案為[-8,1].
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