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答: y=log2(x)+logx(2x) 定義域滿足:x>0,x≠1 根據換底公式有: y=log2(x)+logx(2x) =log2(x)+log2(2x)/log2(x) =log2(x)+[1+log2(x)]/log2(x) =log2(x)+1/log2(x)+1設m=log2(x) =m+1/m+1 1)當0
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