Find the range of function y = log2 (x) + log x (2x)

Find the range of function y = log2 (x) + log x (2x)

A:
y=log2(x)+logx(2x)
The definition field satisfies: x > 0, X ≠ 1
According to the formula of changing the bottom, there are:
y=log2(x)+logx(2x)
=log2(x)+log2(2x)/log2(x)
=log2(x)+[1+log2(x)]/log2(x)
=Log2 (x) + 1 / log2 (x) + 1 let m = log2 (x)
=m+1/m+1
1) When 0