If the two zeros of the function f (x) = xsquare - ax-b are 2 and 3, find loga25 + B2

If the two zeros of the function f (x) = xsquare - ax-b are 2 and 3, find loga25 + B2

That is, 2 and 3 are the roots of X & # 178; - ax-b = 0
SO 2 + 3 = a
2×3=-b
a=5,b=-6
So the original formula = log5 (5 & # 178;) + (- 6) &# 178;
=2+36
=38