If the function f (x) satisfies f (x + 3) = f (- x + 5) in its domain of definition, and the equation f (x) = 0 has five unequal real roots, find these five roots Find the sum of the five real roots

If the function f (x) satisfies f (x + 3) = f (- x + 5) in its domain of definition, and the equation f (x) = 0 has five unequal real roots, find these five roots Find the sum of the five real roots

F (x + 3) = f (- x + 5), so f (x) is symmetric with respect to x = 4
If there are five unequal real roots, then there are two pairs of symmetric real roots about x = 4, and the sum of the four roots is 2 * 2 * 4 = 16
Another real root is exactly 4, so the sum of 5 roots is 20