If f (lgx) > F (1), then the value range of real number x is () A. （110，1）B. （0，110）∪（1，+∞）C. （110，10）D. （0，1）∪（10，+∞）

∵ f (x) is an even function, it is a decreasing function on [0, + ∞), and∵ f (x) increases monotonically on (- ∞, 0). From F (lgx) > F (1), f (1) = f (- 1), we get: - 1 < lgx < 1, ∵ 110 < x < 10, so the answer is C

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