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Let a = {(x, y) | x24 + y216 = 1}, B = {(x, y) | y = 3x}, then the number of subsets of a ∩ B is () A. 4B. 3C. 2D. 1
∩ set a = {(x, y) | x24 + y216 = 1}, ∩ x24 + y216 = 1 is an ellipse and an exponential function y = 3x image. As shown in the figure, we can see that there are two different intersection points, denoted as A1 and A2. Then the subset of a ∩ B should be a total of four kinds, namely, {A1}, {A2}, {A1, A2}
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