The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) (2) Let f ^ 2 (x) - 2x under the function g (x) = root sign, y = 2 ^ (1 / 2) N-X and y = G ^ - 1 (x) respectively The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) (2) Let f ^ 2 (x) - 2x under the function g (x) = root sign, y = 2 ^ (1 / 2) N-X and y = G ^ - 1 (x) respectively Let an be the length of anbn and Sn be the sum of the first n terms of the sequence {an}. When n is greater than or equal to 2, the square of Sn is greater than 2 (S2 / 2 + S3 / 3 +...) +Sn/n)

The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) (2) Let f ^ 2 (x) - 2x under the function g (x) = root sign, y = 2 ^ (1 / 2) N-X and y = G ^ - 1 (x) respectively The function f (x) defined on R satisfies the following conditions: F (x) + F (- x) = 2 pairs of non-zero real numbers x, all of which have 2F (x) + F (1 / x) = 2x + 1 / x + 3. (1) find the analytic expression of F (x) (2) Let f ^ 2 (x) - 2x under the function g (x) = root sign, y = 2 ^ (1 / 2) N-X and y = G ^ - 1 (x) respectively Let an be the length of anbn and Sn be the sum of the first n terms of the sequence {an}. When n is greater than or equal to 2, the square of Sn is greater than 2 (S2 / 2 + S3 / 3 +...) +Sn/n)

Because 2F (x) + F (1 / x) = 2x + 1 / x + 3 (1)
So, if you replace x with 1 / x, you get
2f(1/x)+f(x)=2/x+x+3 (2)
(1) Multiply by 2 and subtract (2)
3f(x)=3x+3
f(x)=x+1
The second question should be more explicit