As shown in the figure, when △ abcab = 7, AC = 11, point m is the midpoint of BC, ad is the bisector of ∠ BAC, and MF ‖ ad, the length of FC is______ ．

As shown in the figure, ∵ ad is the bisector of ∠ BAC, ∵ CDDB = acab = 117, ∵ point m is the midpoint of BC, ∵ cm + dmcm − DM = 117, the solution is CMDM = 92. ∵ MF ∥ ad, ∵ CFFA = cmmd = 92. ∵ CF + FA = 11, ∵ CF = 9

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