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如圖所示,∵AD是∠BAC的平分線,∴CDDB=ACAB=117,∵點M是BC的中點,∴CM+DMCM−DM=117,解得CMDM=92.∵MF‖AD,∴CFFA=CMMD=92.∵CF+FA=11,∴CF=9.
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