The product of (x + 1) (X & # 178; + - 5AX + a) does not contain X & # 178; if the term a = () M & # 178; + M-1 = 0, then M & # 179; + 2m & # 178; + 2013 = () (- 2) to the power of 2012 + (- 2) to the power of 2013 = then the questions and answers of the types frequently tested in the examination and the various types frequently explained in detail must be at least 6

The product of (x + 1) (X & # 178; + - 5AX + a) does not contain X & # 178; if the term a = () M & # 178; + M-1 = 0, then M & # 179; + 2m & # 178; + 2013 = () (- 2) to the power of 2012 + (- 2) to the power of 2013 = then the questions and answers of the types frequently tested in the examination and the various types frequently explained in detail must be at least 6

If the product of (x + 1) (X & # 178; + 5AX + a) does not contain X & # 178; then a = - 0.2
Analysis: (x + 1) (X & # 178; + 5AX + a) = x & # 179; + 5AX & # 178; + ax + X & # 178; + 5AX + a = x & # 179; + (5a + 1) x & # 178; + 6AX + A
M & # 178; + M-1 = 0, then M & # 179; + 2m & # 178; + 2013 = (M & # 179; + M & # 178; - M) + (M & # 178; + m-1) + 2014 = m (M & # 178; + m-1) + (M & # 178; + m-1) + (M & # 178; + m-1) + 2014 = 2014
2012 power of (- 2) + 2013 power of (- 2) = 2012 power of (- 2) ^ 2012 × [1 + (- 2)] = - 2 ^ 2012 = - 2
Method 2
All the terms that can be generated are listed directly. There are only two terms for X & # 178;, - 5AX & # 178;, so a = 0.2
Direct matching, times from high to low
m³+2m²+2013=m(m²+m-1)+(m²+m-1)+2014=2014
Extract the common factor, (- 2) to the power of 2012, the remaining term, 1 + (- 2) = (- 1), the original formula is equal to the power of - 2 to the power of 2012