Let f (x) = {arctan [1 / (x-1)], X not equal to 1,0, x = 1. Find the limit of F (x), X tends to 1 minus, and the limit of F (x), X tends to 1 plus
When x → 1 +, 1 / (x-1) → + ∞, arctan (1 / (x-1) → π / 2, Lin (x → 1 +) f (x) = π / 2,
When x → 1 -, 1 / (x-1) → - ∞, arctan (1 / (x-1) → - π / 2, Lin (x → 1 +) f (x) = - π / 2
RELATED INFORMATIONS
- 1. Find the left and right limit, and determine whether the limit of function at this point exists, f (x) = arctan (1 / x), x = 0
- 2. Limx - > ∞ arctan (√ x2 + 2x-x) how to use the continuity of function to find the limit and kneel down to find the answer It's the square of the root x plus 2x, and then minus X.
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- 9. If A.B.C is a three digit number of hundred, ten and one, and a ≤ B ≤ C, then the maximum value of | A-B | + | B-C | + | C-A |,
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- 18. Math problem arithmetic problem is very simple 200 - 500 = how much is it to solve a good mathematical answer
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