Y = [the square of (x1-x) plus the square of (x2-x) plus the square of x3-x] divided by 3

Y = [the square of (x1-x) plus the square of (x2-x) plus the square of x3-x] divided by 3

X is equal to the average of X1 + x2 + X3, that is to say, when x is close to x1, X2 and X3 at the same time, y takes the minimum value
You can take a special case, suppose X1 = x2 = X3
This will be learned in the inequality of high 2. Don't worry